# 6. Some introductory examples.

Example 2: Consider the system If we differentiate the first equation on time we get that inserted into the second implies that This differential equation has the solution for some constants a and b. Since y is the derivative of x we have Finally we note that where c is a constant. The only equilibrium point obviously is (0,0). The phase portrait looks like this: Remark: The relation x2+y2=c2 may also be obtained in the following way: where Example 3:
Consider the system This decoupled system has the solution where c1 and c2 are two arbitrary constants. To draw the phase portrait we solve the equation The phase portrait thus becomes: Example 4: Every second order differential equation can be written as a system of first order differential equations Example 5: The equation of the pendulum (see e.g. chapter 7) can be written as the system We get the equilibrium points when that is, they are Here are stable equilibrium points (colored green in the phase portrait) and unstable equilibrium points (colored red in the phase portrait). Example 6: Van der Pols equation can be written as where is a (small) parameter. Here we have an (unstable) equilibrium point (0,0) (red color) and if we look at the phase portrait we see that we also have a limit cycle. This limit cycle (green color) is stable (all solutions in the neighborhood will be attracted to the limit cycle). We have plotted the phase portrait below for . Example 7:
Predators and prey, Volterra’s model.
There are two different species of fish in a lake: A (prey), that feeds off sea weeds (which is abundant) and B (predator), that feeds off the prey A.

The more prey A we have, the higher growth of A since the sea weed can be supposed to be enough to feed all. On the other hand, the growth of A is limited by the number of encounters between A and B, since they lead to that A being eaten. The more predators B, the lower growth of B since then we will have bigger concurrence about the prey A. On the other hand, the growth increases with the number of encounters between A and B, since Bgets food this way. If conclude  the above reasoning, we get Volterra‘s model where a, b, c, d are positive constants, x=x(t) the population of A and y=y(t) the population of B at time t.

We get the equilibrium points by solving the system that is We have two possibilities for both equations to become zero. Either we have (x,y)=(0,0) or we have (x,y)=(b/d,a/c). If we draw the phase portrait we see thatthe first point is unstable while the second is stable. This model is useful to explain many well known biological phenomena when we have some kind of competition between different animals, for instance foxes and rabbits.