9. Some more examples.

Example 7: Determine the shortest curve y=y(x), y(0)=a, y(1)=b, that spans the area A together with the coordinate axes and the line x=1.

 

Solution: The problem thus means that we should minimize the functional

under the constraint

 

where

 

By using the method from the previous part we must construct the functional

A necessary condition for minimum is that

 

fulfills Euler’s equation

 

Integration now gives

If we integrate again we see that 

 

that is

 

which is a circle. The unknown constants  , d0 and c are deterermined from the three conditions

 


Example 8:
 (Chain line). A rope of length l and constant mass  per unit length hangs between two fixed points (a,y
1) and (b,y2) in the plane. What shape y(x) will the rope attain?


Solution: A small element ds in the point (x,y) has the mass 


and the potential energy 

 

with respect to y=0. The total potential energy is thus

 

The rope assumes a shape such that the potential energy is minimized. This means that we should minimize J(y) under the constraint of constant length

 

We thus construct 

 

and put it into the Euler equation. However, in this case L* does not explicitly depend on x and we can thus use Beltrami’s identity

 

that is

 

If we solve for y’ we get 

 

This is a separable differential equation. Hence integration gives

 

We now make the change of variables

 

and then the left hand side integral transforms to

 

We multiply with  and then take cosh(.) on both sides of the equality sign and use that it is an even function. We get

 

If we finally solve for y we get

 

This means that the shape of a hanging rop is a catenary (or chain line). The constants C, C2 and  are determined by the boundary conditions and the curve length.

Example 9: Find the extremals to the triple integral

under the constraint 

 

We thus construct

 

The Euler equation in this case becomes 

 

that is

 

This is the famous Schrödinger equation in quantum mechanics for a particle of mass m under the influence of a potential V. In this case D is R3and the constraints is the normalized probability condition for the wave function  , whose square is a probablility density (a measure of where a particle most likely will be). In general we can only find solutions  for particular discrete values of the multiplier  , identified as the possible energy levels that the particla may have.

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